甘草山楂茶

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贡献者回答There are a few different ways to approach this problem, but one possible solution is to use a loop to iterate through each element in the list and check if it is equal to the target number. If it is, you can return the index of that element. If the loop finishes without finding a match, you can return -1 to indicate that the target number was not found in the list.Here is an example implementation in Python:def linear_search(arr, target): for i in range(len(arr)): if arr[i] == target: return i return -1# Example usagearr = [4, 7, 2, 9, 1]target = 9print(linear_search(arr, target)) # Output: 3In this example, the linear_search function takes two arguments: the list to search in (arr) and the target number to search for (target). The function uses a for loop to iterate through each element in the list, checking if it is equal to the target number. If a match is found, the index of that element is returned. If the loop finishes without finding a match, -1 is returned.In the example usage, the function is called with the list [4, 7, 2, 9, 1] and the target number 9. The output is 3, indicating that the target number was found at index 3 in the list.

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